Question

The pressure of a nitrogen gas, N2, cylinder is measured at 250 K and found to be 4.0 atm. What is the pressure of the same cylinder at room temperature, 293 K?

Answers

There are no human answers yet.
Answered by GPT 3.5
To solve this problem, we can use the ideal gas law:

PV = nRT

Where:
P = pressure
V = volume
n = number of moles
R = ideal gas constant
T = temperature in Kelvin

Since we are looking for the final pressure at room temperature, we can write the equation as:

P1V1/T1 = P2V2/T2

Given:
P1 = 4.0 atm
V1 = unknown (since it does not change)
T1 = 250 K
P2 = unknown
V2 = unknown (since it does not change)
T2 = 293 K

We can rearrange the equation to solve for P2:

P2 = P1 * (T2 / T1)

Substitute the given values into the equation:

P2 = 4.0 atm * (293 K / 250 K)
P2 = 4.0 atm * 1.172
P2 = 4.688 atm

Therefore, the pressure of the same nitrogen gas cylinder at room temperature (293 K) would be 4.688 atm.

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