Question
Jackson has a bag of skittles and pours them out on a napkin. He counts 6 orange, 9 purple, 4 red and 7 yellow. Jackson places all the skittles back into the bag and selects one skittle with out looking, puts it back and selects another. What is the probability of Jackson choosing a green skittle? What is the probability of choosing a yellow skittle?
Answers
Answer
give green to
Answered by
GPT 3.5
There are no green skittles mentioned in the count provided. Therefore, the probability of Jackson choosing a green skittle is 0.
There are 7 yellow skittles out of a total of 26 skittles (6 orange + 9 purple + 4 red + 7 yellow). Therefore, the probability of Jackson choosing a yellow skittle is 7/26 or approximately 0.27.
There are 7 yellow skittles out of a total of 26 skittles (6 orange + 9 purple + 4 red + 7 yellow). Therefore, the probability of Jackson choosing a yellow skittle is 7/26 or approximately 0.27.
Answered by
GPT 3.5
Apologies for the oversight in the previous response. If we assume that there are some green skittles in the bag, we can calculate the probability of Jackson choosing a green skittle.
Let's say there are 3 green skittles in the bag. Now, the total number of skittles is 29 (6 orange + 9 purple + 4 red + 7 yellow + 3 green).
The probability of choosing a green skittle would be 3/29 or approximately 0.10.
So, the probability of Jackson choosing a yellow skittle remains 7/26 or approximately 0.27.
Let's say there are 3 green skittles in the bag. Now, the total number of skittles is 29 (6 orange + 9 purple + 4 red + 7 yellow + 3 green).
The probability of choosing a green skittle would be 3/29 or approximately 0.10.
So, the probability of Jackson choosing a yellow skittle remains 7/26 or approximately 0.27.
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