Question
What is the molar mass of a gas if 142g of the gas occupies a volume of 45.1 L at 28.4C and 94.6 kPa?
Answers
GPT 3.5
To calculate the molar mass of the gas, we first need to convert the given values to appropriate units.
Using the ideal gas law equation:
PV = nRT
Where:
P = pressure in atm (94.6 kPa = 0.935 atm)
V = volume in L (45.1 L)
n = moles
R = gas constant (0.0821 L.atm/mol.K)
T = temperature in Kelvin (28.4 + 273.15 = 301.55 K)
From the given information, we can rearrange the equation to solve for moles:
n = PV / RT
n = (0.935 atm) * (45.1 L) / (0.0821 L.atm/mol.K * 301.55 K)
n = 1.748 moles
Now, we can calculate the molar mass of the gas:
Molar mass = mass / moles
Molar mass = 142 g / 1.748 mol
Molar mass = 81.19 g/mol
Therefore, the molar mass of the gas is 81.19 g/mol.
Using the ideal gas law equation:
PV = nRT
Where:
P = pressure in atm (94.6 kPa = 0.935 atm)
V = volume in L (45.1 L)
n = moles
R = gas constant (0.0821 L.atm/mol.K)
T = temperature in Kelvin (28.4 + 273.15 = 301.55 K)
From the given information, we can rearrange the equation to solve for moles:
n = PV / RT
n = (0.935 atm) * (45.1 L) / (0.0821 L.atm/mol.K * 301.55 K)
n = 1.748 moles
Now, we can calculate the molar mass of the gas:
Molar mass = mass / moles
Molar mass = 142 g / 1.748 mol
Molar mass = 81.19 g/mol
Therefore, the molar mass of the gas is 81.19 g/mol.