what is the concentration (M) of CH3OH in a solution prepared by dissolving 25.3 g of CH3OH in sufficient water to give exactly 230 mL of solution

Answer 1

To calculate the concentration of CH3OH in the solution, we first need to calculate the number of moles of CH3OH in the solution.

1. Calculate the molar mass of CH3OH:
(1 x 12.01 g/mol) + (4 x 1.008 g/mol) + 16.00 g/mol
= 32.04 g/mol

2. Calculate the number of moles of CH3OH in 25.3 g:
25.3 g / 32.04 g/mol = 0.790 mol

3. Calculate the concentration of CH3OH in the solution:
Concentration (M) = moles / volume (L)
Volume = 230 mL = 0.230 L

Concentration (M) = 0.790 mol / 0.230 L
Concentration (M) = 3.43 M

Therefore, the concentration of CH3OH in the solution is 3.43 M.