Systems of Linear Equations Unit Test

To solve this system of equations, we can use the substitution method.

From the first equation, we can rearrange it to solve for x:
-6x + 2y = -32
-6x = -2y - 32
x = (2y + 32) / 6

Now we can substitute this expression for x into the second equation:
4((2y + 32) / 6) + 3y = -9
(8y + 128) / 6 + 3y = -9
(8y + 128 + 18y) / 6 = -9
26y + 128 = -54
26y = -182
y = -7

Now that we have found the value of y, we can substitute it back into the expression for x:
x = (2(-7) + 32) / 6
x = (-14 + 32) / 6
x = 18 / 6
x = 3

Therefore, the solution to the system of equations is:
(3, -7)