Solution-Diluent Volume Ratios: Write the complete solutions.

Calculate the p-value for each of the indicated ions: Na+, Cl-, and OH- in a solution that is 0.0635 M in NaCl and 0.0403 M in NaOH

1 answer

To calculate the p-value for each ion, we need to determine the diluent volume ratios for Na+, Cl-, and OH- in the solution.

Given:
- Concentration of NaCl = 0.0635 M
- Concentration of NaOH = 0.0403 M

First, let's calculate the moles of Na+ and Cl- ions present in the solution:
Moles of NaCl = Concentration of NaCl x Volume of solution
Moles of NaCl = 0.0635 mol/L x V L

Assuming the volume of the solution is 1 L (for simplicity), moles of NaCl = 0.0635 mol

Since NaCl dissociates into Na+ and Cl- ions in a 1:1 ratio, the moles of Na+ and Cl- ions will be equal.

Next, let's calculate the moles of NaOH in the solution:
Moles of NaOH = Concentration of NaOH x Volume of solution
Moles of NaOH = 0.0403 mol/L x V L

Assuming the volume of the solution is 1 L (for simplicity), moles of NaOH = 0.0403 mol

Since NaOH dissociates into Na+ and OH- ions in a 1:1 ratio, the moles of Na+ and OH- ions will be equal.

Therefore, the moles of Na+ ions in the solution = 0.0635 mol (from NaCl) + 0.0403 mol (from NaOH) = 0.1038 mol

Similarly, the moles of Cl- ions in the solution = 0.0635 mol

And the moles of OH- ions in the solution = 0.0403 mol

Now, we can calculate the p-value for each ion using the formula:
p-value = -log10([ion]/[diluent])

Since the diluent for this solution is water, which does not contain any of the specific ions, we can assume the ion concentration in the diluent is negligible (close to 0).

Therefore, for all three ions (Na+, Cl-, and OH-):
p-value = -log10([ion] / 0)
p-value = -log10(0) = Undefined

Therefore, the p-value for Na+, Cl-, and OH- ions in this solution is undefined.