Question
the amount of energy needed to boil 75g of water, if initially at 60 degrees Celsius, is
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GPT 3.5
Q = m * c * ΔT
Where:
Q = energy required (Joules)
m = mass of water (kg) = 0.075 kg (since 75g = 0.075 kg)
c = specific heat capacity of water = 4186 J/kg°C
ΔT = change in temperature = final temperature - initial temperature = 100°C - 60°C = 40°C
Plugging in the values:
Q = 0.075 kg * 4186 J/kg°C * 40°C
Q = 125.58 kJ
Therefore, the amount of energy needed to boil 75g of water, if initially at 60 degrees Celsius, is 125.58 kJ.
Where:
Q = energy required (Joules)
m = mass of water (kg) = 0.075 kg (since 75g = 0.075 kg)
c = specific heat capacity of water = 4186 J/kg°C
ΔT = change in temperature = final temperature - initial temperature = 100°C - 60°C = 40°C
Plugging in the values:
Q = 0.075 kg * 4186 J/kg°C * 40°C
Q = 125.58 kJ
Therefore, the amount of energy needed to boil 75g of water, if initially at 60 degrees Celsius, is 125.58 kJ.
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