Asked by Shanta
Posted a question earlier but it was the wrong question. If anyone could help it would great if you could explain this would help also.
Thanks
^ = subscript
Calculate ke for(equlibrium concentration below problem
2CO^2(g) + heat 2CO(g) + O^2
[0.103] [0.024] [1.18 x 10^2]
Thanks
^ = subscript
Calculate ke for(equlibrium concentration below problem
2CO^2(g) + heat 2CO(g) + O^2
[0.103] [0.024] [1.18 x 10^2]
Answers
Answered by
DrBob222
1. You have no arrow. How do we separate the reactants from the products? I assume it is
2CO2 + heat ==> 2CO + O2
2. You don't need to write ^ for subscripts. The ^ sign is reserved for exponents and on these boards it is understood that we can't write subscripts; therefore, NO2 means NO<sub>2</sub>. 10^-3 means 10<sup>-3</sup>.
3. What is the Ke expression? Isn't it
(CO)^2(O2)/(CO2)^2
4. If that second line you have denotes equilibrium concentrations, just plug into the appropriate boxes in the Ke expression (written in 3 above) and calculate.
2CO2 + heat ==> 2CO + O2
2. You don't need to write ^ for subscripts. The ^ sign is reserved for exponents and on these boards it is understood that we can't write subscripts; therefore, NO2 means NO<sub>2</sub>. 10^-3 means 10<sup>-3</sup>.
3. What is the Ke expression? Isn't it
(CO)^2(O2)/(CO2)^2
4. If that second line you have denotes equilibrium concentrations, just plug into the appropriate boxes in the Ke expression (written in 3 above) and calculate.
Answered by
D
Not sure, sorry.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.