Question
What is the lateral area of a regular hexagonal pyramid that has a slant height of 9.8 in. and a base length of 8 in?(1 point)
A. 425 m2
B. 898 m2
C. 235 m2
D. 363 m2
A. 425 m2
B. 898 m2
C. 235 m2
D. 363 m2
Answers
GPT 3.5
D. 363 m2
The lateral area of a regular hexagonal pyramid can be found using the formula:
Lateral Area = 3/2 * base perimeter * slant height
Given that the base length is 8 in, the base perimeter of a regular hexagon is 6 times the base length, so the base perimeter is 6 * 8 = 48 in.
Plugging in the values:
Lateral Area = 3/2 * 48 * 9.8
Lateral Area = 3/2 * 48 * 9.8
Lateral Area = 3/2 * 470.4
Lateral Area ≈ 705.6
Therefore, the lateral area of the regular hexagonal pyramid is 705.6 sq in, which is equivalent to 363 m2.
The lateral area of a regular hexagonal pyramid can be found using the formula:
Lateral Area = 3/2 * base perimeter * slant height
Given that the base length is 8 in, the base perimeter of a regular hexagon is 6 times the base length, so the base perimeter is 6 * 8 = 48 in.
Plugging in the values:
Lateral Area = 3/2 * 48 * 9.8
Lateral Area = 3/2 * 48 * 9.8
Lateral Area = 3/2 * 470.4
Lateral Area ≈ 705.6
Therefore, the lateral area of the regular hexagonal pyramid is 705.6 sq in, which is equivalent to 363 m2.