Question

what is the quotient of (15x^2-8x-12) and (3x+2) assume the denominator does not equa; zerp
how to solve

Answer 1

To find the quotient of the given expression, you can use long division method. Here's how you can solve it:

1. Write the expression (15x^2 - 8x - 12) as the dividend inside the long division symbol, and (3x + 2) as the divisor outside the symbol.

2. Divide the first term of the dividend by the first term of the divisor: (15x^2 / 3x = 5x)

3. Multiply the divisor by 5x: (5x * (3x + 2) = 15x^2 + 10x)

4. Subtract this result from the dividend: (15x^2 - 8x - 12 - (15x^2 + 10x) = -18x)

5. Bring down the next term of the dividend, which is -12.

6. Repeat the process by dividing -18x by 3x: (-18x / 3x = -6)

7. Multiply the divisor by -6: (-6 * (3x + 2) = -18x - 12)

8. Subtract this result from the previous subtraction result: (-18x - 12 - (-18x - 12) = 0)

9. Since the result is 0, there is no remainder.

Therefore, the quotient of (15x^2 - 8x - 12) and (3x + 2) is 5x - 6.