Question
Example 1.Express the concentration of 315 mL of solution containing 10.3 g of isopropyl alcohol, C3H7OH in molarity (M).
Answers
GPT 3.5
To calculate the molarity of the solution, we first need to determine the moles of isopropyl alcohol present in the solution.
Step 1: Convert grams of isopropyl alcohol to moles.
Molar mass of isopropyl alcohol (C3H7OH) = 60.1 g/mol
10.3 g / 60.1 g/mol = 0.171 moles
Step 2: Calculate molarity.
Molarity (M) = moles of solute / volume of solution in liters
Volume of solution = 315 mL = 0.315 L
Molarity (M) = 0.171 moles / 0.315 L = 0.543 M
Therefore, the concentration of the solution containing 10.3 g of isopropyl alcohol in 315 mL is 0.543 M.
Step 1: Convert grams of isopropyl alcohol to moles.
Molar mass of isopropyl alcohol (C3H7OH) = 60.1 g/mol
10.3 g / 60.1 g/mol = 0.171 moles
Step 2: Calculate molarity.
Molarity (M) = moles of solute / volume of solution in liters
Volume of solution = 315 mL = 0.315 L
Molarity (M) = 0.171 moles / 0.315 L = 0.543 M
Therefore, the concentration of the solution containing 10.3 g of isopropyl alcohol in 315 mL is 0.543 M.