Asked by Taylor
How do you factor and simplify,
1-sin^3x
and
sec^4x-2sec^2xtan^2x+tan^4x
1-sin^3x
and
sec^4x-2sec^2xtan^2x+tan^4x
Answers
Answered by
bobpursley
the first is the difference of two cubes:
(1-a^3)=(1-a)(1+a+a^2)
from...
a3 – b3 = (a – b)(a2 + ab + b2)
the second is very similar to
(a^2-2ab+b^2).....
(1-a^3)=(1-a)(1+a+a^2)
from...
a3 – b3 = (a – b)(a2 + ab + b2)
the second is very similar to
(a^2-2ab+b^2).....
Answered by
Taylor
I'm not positive, but the answer to 1-sin^3 would be (1-sinx)(1+sinx+sin^2x)
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