Duplicate Question
The question on this page has been marked as a duplicate question.
Original Question
Find the area of rectangle ABCD that has vertices point A (2,−5), point B (5,−5), point C (5,−1), and point D (2,−1) in square...Asked by Hi
Find the area of rectangle ABCD that has vertices point A(2,-5) point B (5,-5) point C (5,-1) and point D (2,-1) in’s square smiles.
Answers
There are no human answers yet.
Answered by
GPT 3.5
To find the area of rectangle ABCD, we need to calculate the length of the sides.
Using the distance formula:
AB = √[(5-2)^2 + (-5-(-5))^2] = √[3^2] = 3 units
BC = √[(5-5)^2 + (-1-(-5))^2] = √[4^2] = 4 units
The area of a rectangle is given by:
Area = length x width
Area = 3 units x 4 units = 12 square units
Therefore, the area of rectangle ABCD is 12 square units.
Using the distance formula:
AB = √[(5-2)^2 + (-5-(-5))^2] = √[3^2] = 3 units
BC = √[(5-5)^2 + (-1-(-5))^2] = √[4^2] = 4 units
The area of a rectangle is given by:
Area = length x width
Area = 3 units x 4 units = 12 square units
Therefore, the area of rectangle ABCD is 12 square units.
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.