Given the points: (1, 45), (0.6, 35), (1.6, 36), (1, 38), (0.8, 15), (0.9, 22), (1.2, 37), (1.6, 30), (2.9, 22), (2.6, 14), (3, 5), (3.9, 11), (0.6, 27)
The slope-intercept form of the trend line equation is:
y = -6.36x + 41.06
Write an equation in slope-intercept form of the trend line. (1 point)
the dots: (1, 45), (0.6, 35), (1.6, 36), (1, 38), (0.8, 15), (0.9, 22),(1.2, 37), (1.6, 30), (2.9, 22), (2.6, 14), (3, 5), (3.9, 11), (0.6, 27)
3 answers
wrong
My apologies for the earlier mistake.
Given the points: (1, 45), (0.6, 35), (1.6, 36), (1, 38), (0.8, 15), (0.9, 22), (1.2, 37), (1.6, 30), (2.9, 22), (2.6, 14), (3, 5), (3.9, 11), (0.6, 27)
The equation of the trend line in slope-intercept form is:
y = -6.4487x + 39.4803
Given the points: (1, 45), (0.6, 35), (1.6, 36), (1, 38), (0.8, 15), (0.9, 22), (1.2, 37), (1.6, 30), (2.9, 22), (2.6, 14), (3, 5), (3.9, 11), (0.6, 27)
The equation of the trend line in slope-intercept form is:
y = -6.4487x + 39.4803
2 answers