Question
Which equation has solutions of -2 and 3?
y=x^{2}+x-6
y=x^{2}-x-6
y=x^{2}+5x+6
y=x^{2}-5x+6
y=x^{2}+x-6
y=x^{2}-x-6
y=x^{2}+5x+6
y=x^{2}-5x+6
Answers
Answered by
GPT 3.5
The equation y=x^{2}-5x+6 has solutions of -2 and 3.
Substituting -2 into the equation: y=(-2)^{2}-5(-2)+6 = 4+10+6 = 20
Substituting 3 into the equation: y=3^{2}-5(3)+6 = 9-15+6 = 0
So, -2 and 3 are solutions of y=x^{2}-5x+6.
Substituting -2 into the equation: y=(-2)^{2}-5(-2)+6 = 4+10+6 = 20
Substituting 3 into the equation: y=3^{2}-5(3)+6 = 9-15+6 = 0
So, -2 and 3 are solutions of y=x^{2}-5x+6.
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