write the equation of a linear function that passes through the points (2, 2) and (0, 3)

Answer 1

First, calculate the slope of the line using the two points:

m = (y2 - y1) / (x2 - x1)
m = (3 - 2) / (0 - 2)
m = 1 / -2
m = -1/2

Now that we have the slope, we can use one of the points to find the y-intercept (b).

Using the point (2, 2):

2 = (-1/2)(2) + b
2 = -1 + b
b = 3

Now we can write the equation of the line in slope-intercept form:

y = -1/2x + 3

Thus, the equation of the linear function that passes through the points (2, 2) and (0, 3) is y = -1/2x + 3.