To find when the object hits the ground, we need to find when the height of the object is 0.
h(t) = -16t^2 + 144
Setting h(t) = 0:
0 = -16t^2 + 144
16t^2 = 144
t^2 = 9
t = 3 or t = -3
Since time cannot be negative, the object will hit the ground after 3 seconds.
So, the answer is 3s.
If an object is dropped from a height of 144 ft, the function h(t) = - 16c ^ 2 + 144 gives the height of the object after t seconds. When will the object hit the ground?
(1 point)
1.5 s
Ο 35
68
O9s
1 answer