Using the change of base formula for logarithms, we have:
\log_6 1296 = \frac{\log_{10}1296}{\log_{10}6}
Using a calculator to find the logarithms, we get:
\log_{10}1296 ≈ 3.11
\log_{10}6 ≈ 0.778
Therefore, \log_6 1296 ≈ \frac{3.11}{0.778} ≈ 3.99.
Thus, the value of \log_6 1296 is approximately 3.99.
Evaluate the logarithm.
\log_61296
1 answer
1 answer