The pH of [H3O+] = 0.00020 can be calculated using the formula:
pH = -log[H3O+]
Substitute the given value:
pH = -log(0.00020)
pH = 3.70
Therefore, the pH of [H3O+] = 0.00020 is 3.70.
Poh of [H3O+] = 0.00020
1 answer