To find the vertex of the function, we first need to find the x-coordinate of the vertex, which is given by the formula x = -b/(2a) where a = 3 and b = -6 in this case.
x = -(-6)/(2*3)
x = 6/6
x = 1
Now that we have found the x-coordinate of the vertex, we can substitute this back into the original function to find the y-coordinate.
f(1) = 3(1)^2 - 6(1) + 4
f(1) = 3(1) - 6 + 4
f(1) = 3 - 6 + 4
f(1) = 1
Therefore, the vertex of the function f(x) = 3x^2 - 6x + 4 is (1, 1).
Find the vertex of the function
f(x) = 3x^2 - 6x + 4
1 answer