. Bowl a contains 3 white balls and 2 red balls, while bowl b contains 2 white balls and 4 red balls.
If a ball is randomly chosen from each bowl, the probability of selecting a white ball from bowl a is \( 3/5 \) and the probability of selecting a white ball from bowl b is \( 2/6 = 1/3 \).
Overall, the probability of selecting a white ball from either bowl a or b can be calculated as the sum of the individual probabilities:
\[ P(\text{selecting a white ball from either bowl a or b}) = P(\text{selecting a white ball from bowl a}) + P(\text{selecting a white ball from bowl b}) \]
\[ = \frac{3}{5} + \frac{1}{3} \]
\[ = \frac{9}{15} + \frac{5}{15} \]
\[ = \frac{14}{15} \]
Therefore, the probability of selecting a white ball from either bowl a or b is \( \frac{14}{15} \).
Bowls a and b contain a number of white and red balls
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