12.1 g
The mass in grams of ammonium chloride required can be calculated using the formula:
mass = moles x molar mass
First, calculate the moles of NH4Cl:
moles = Molarity x Volume
moles = 0.35 mol/L x 0.250 L
moles = 0.0875 mol
Next, calculate the mass:
mass = 0.0875 mol x 53.5 g/mol
mass = 4.689 g
Therefore, the mass in grams of ammonium chloride required is 4.7 g.
Determine the mass in grams of ammonium chloride, NH4CI, required to prepare 0.250 L of a 0.35 M solution of ammonium chloride.
*NH4CI molar mass is 53.5 g
4.7 g
0.002 g
0.089 g
12.1 g
1 answer
1 answer