Solve the system of two equations using elimination with multiplication. 4x−6y=−48 −2x+4y=30(1 point) Responses (3, 9) left parenthesis 3 comma 9 right parenthesis (−33,−9). What’s the answer

Answer 1

To solve this system of equations using elimination with multiplication, we need to make the coefficients of one of the variables the same in both equations.

First, let's multiply the second equation by 2 to make the coefficients of x equal but opposite in sign:

-2x + 4y = 30
4x - 8y = 60

Next, add the two equations together to eliminate x:

4x - 6y = -48
4x - 8y = 60

0x - 14y = 12

Now, divide both sides by -14 to solve for y:

y = -12/14
y = -6/7

Now, substitute y back into one of the original equations to solve for x. Let's use the first equation:

4x - 6(-6/7) = -48
4x + 36/7 = -48
4x = -336/7 - 36/7
4x = -372/7
x = -93/7

Therefore, the solution to the system of equations is:
x = -93/7
y = -6/7

So the answer is (-93/7, -6/7).