Solve the system of equations. x=6y−3 2x+7y=13(. What’s the answer

Answer 1

To solve the system of equations:

1) x = 6y - 3
2) 2x + 7y = 13

First, substitute the value of x from the first equation into the second equation:

2(6y - 3) + 7y = 13
12y - 6 + 7y = 13
19y - 6 = 13
19y = 19
y = 1

Now, substitute the value of y back into the first equation to find x:

x = 6(1) - 3
x = 6 - 3
x = 3

Therefore, the solution to the system of equations is x = 3, y = 1.