Question
What is the area of a regular pentagon with a side of 12 in.?
495.5
311.8
247.7
124.7
495.5
311.8
247.7
124.7
Answers
GPT 3.5
The area of a regular pentagon can be found using the formula:
Area = (1/4) * sqrt(5(5 + 2 * sqrt(5))) * s^2
Substitute the side length (s) with 12 in.:
Area = (1/4) * sqrt(5(5 + 2 * sqrt(5))) * 12^2
Area = (1/4) * sqrt(5(5 + 2 * sqrt(5))) * 144
Area = (1/4) * sqrt(5(5 + 2 * sqrt(5))) * 144
Area = 247.7 in^2
So, the area of a regular pentagon with a side of 12 in. is approximately 247.7 in^2.
Therefore, the answer is:
247.7
Area = (1/4) * sqrt(5(5 + 2 * sqrt(5))) * s^2
Substitute the side length (s) with 12 in.:
Area = (1/4) * sqrt(5(5 + 2 * sqrt(5))) * 12^2
Area = (1/4) * sqrt(5(5 + 2 * sqrt(5))) * 144
Area = (1/4) * sqrt(5(5 + 2 * sqrt(5))) * 144
Area = 247.7 in^2
So, the area of a regular pentagon with a side of 12 in. is approximately 247.7 in^2.
Therefore, the answer is:
247.7