Using the quadratic formula:
g = (-b ± √(b^2 - 4ac)) / 2a
In this case, a = -9, b = 6, and c = -1. Plugging these values into the formula:
g = (-(6) ± √((6)^2 - 4(-9)(-1))) / 2(-9)
g = (-6 ± √(36 - 36)) / -18
g = (-6 ± √0) / -18
g = (-6) / -18
g = 1/3
Therefore, the solutions are:
g = 1/3
or g = 1/3
Solve using the quadratic formula.
–9g2 + 6g − 1 = 0
Write your answers as integers, proper or improper fractions in simplest form, or decimals rounded to the nearest hundredth.
g =
or g =
1 answer