To solve the quadratic equation 4w^2 + 4w + 1 = 0 using the quadratic formula:
First, identify the coefficients: a = 4, b = 4, c = 1
The quadratic formula is given by:
w = (-b ± √(b^2 - 4ac)) / 2a
Substitute the values of a, b, and c into the formula:
w = (-4 ± √(4^2 - 4*4*1)) / 2*4
w = (-4 ± √(16 - 16)) / 8
w = (-4 ± √0) / 8
w = (-4 ± 0) / 8
w = -4 / 8
w = -1/2
Therefore, the solutions to the quadratic equation 4w^2 + 4w + 1 = 0 are:
w = -1/2
Solve using the quadratic formula.
4w2 + 4w + 1 = 0
Write your answers as integers, proper or improper fractions in simplest form, or decimals rounded to the nearest hundredth.
w =
or w =
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