To solve the equation –3j^2 − 9j − 4 = 0 using the quadratic formula, we first need to identify the coefficients:
a = -3
b = -9
c = -4
Now, we can plug these values into the quadratic formula:
j = (-b ± √(b^2 - 4ac)) / 2a
j = (9 ± √((-9)^2 - 4*(-3)*(-4))) / 2*(-3)
j = (9 ± √(81 - 48)) / -6
j = (9 ± √33) / -6
Therefore, the solutions for j are:
j = (9 + √33) / -6
j = (9 - √33) / -6
Rounded to the nearest hundredth, the solutions are:
j ≈ -1.05
j ≈ -1.95
Solve using the quadratic formula.
–3j2 − 9j − 4 = 0
Write your answers as integers, proper or improper fractions in simplest form, or decimals rounded to the nearest hundredth.
j =
or j =
1 answer