To solve the equation 8z^2 + 4z = 0 using the quadratic formula, first recognize that this equation is in the form az^2 + bz + c = 0, where a = 8, b = 4, and c = 0.
The quadratic formula is: z = (-b ± √(b^2 - 4ac)) / 2a
Plugging in the values:
z = (-4 ± √(4^2 - 4(8)(0))) / 2(8)
z = (-4 ± √(16)) / 16
z = (-4 ± 4) / 16
Now we have two possible solutions:
z = (-4 + 4) / 16 = 0 / 16 = 0
z = (-4 - 4) / 16 = -8 / 16 = -0.5
So, the solutions are:
z = 0 or z = -0.5
Solve using the quadratic formula.
8z2 + 4z = 0
Write your answers as integers, proper or improper fractions in simplest form, or decimals rounded to the nearest hundredth.
z =
or z =
1 answer
1 answer