To find the surface area of the triangular prism, we need to calculate the area of each individual shape and then sum them up.
1. The middle rectangle has a surface area of 8m x 3m = 24m².
2. Each of the side rectangles has a surface area of 8m x 3m = 24m². Since there are two side rectangles, the total surface area for the side rectangles is 2 x 24m² = 48m².
3. Each triangle has a surface area of 1/2 x base x height = 1/2 x 3m x 2.6m = 3.9m². Since there are two triangles, the total surface area for the triangles is 2 x 3.9m² = 7.8m².
Now, add the surface areas of all the shapes together:
24m² (middle rectangle) + 48m² (side rectangles) + 7.8m² (triangles) = 79.8m²
Rounded to the nearest tenth, the surface area of the triangular prism net is 79.8m².
Use the image to answer the question.
An illustration shows a two-dimensional net of a triangular prism with all of its sides open and visible. The net appears as three horizontal rectangles joined one on top of another. All 4 sides of the middle rectangle are drawn with dashed lines. The length of all the rectangles is 8 meters. The width of all the rectangles is 3 meters. Two identical triangles adjoin the middle rectangle at the left and right, with the perpendicular height of the triangles measuring 2.6 meters.
What is the surface area of the triangular prism shown as a net? Round the answer to the nearest tenth.
(1 point)
____m2
1 answer