Question
Jenny is painting a flatten shoebox for a school project. The shoebox measures 72.5 cm x 47.5 cm x 104 cm what is the area that would be identified on the boxes net
Answers
Answered by
GPT 3.5
The net of the shoebox would include the six faces of the box.
The dimensions of the shoebox are:
Length = 72.5 cm
Width = 47.5 cm
Height = 104 cm
The net would consist of:
- 2 rectangles with dimensions 72.5 cm x 47.5 cm (front and back faces)
- 2 rectangles with dimensions 72.5 cm x 104 cm (side faces)
- 2 rectangles with dimensions 47.5 cm x 104 cm (top and bottom faces)
Calculating the area of each face:
Front and back faces: 72.5 cm x 47.5 cm = 3443.75 cm² each
Side faces: 72.5 cm x 104 cm = 7540 cm² each
Top and bottom faces: 47.5 cm x 104 cm = 4940 cm² each
Adding the areas of all faces together:
2(3443.75) + 2(7540) + 2(4940) = 6887.5 + 15080 + 9880 = 31847.5 cm²
Therefore, the total area of the shoebox net is 31847.5 cm².
The dimensions of the shoebox are:
Length = 72.5 cm
Width = 47.5 cm
Height = 104 cm
The net would consist of:
- 2 rectangles with dimensions 72.5 cm x 47.5 cm (front and back faces)
- 2 rectangles with dimensions 72.5 cm x 104 cm (side faces)
- 2 rectangles with dimensions 47.5 cm x 104 cm (top and bottom faces)
Calculating the area of each face:
Front and back faces: 72.5 cm x 47.5 cm = 3443.75 cm² each
Side faces: 72.5 cm x 104 cm = 7540 cm² each
Top and bottom faces: 47.5 cm x 104 cm = 4940 cm² each
Adding the areas of all faces together:
2(3443.75) + 2(7540) + 2(4940) = 6887.5 + 15080 + 9880 = 31847.5 cm²
Therefore, the total area of the shoebox net is 31847.5 cm².