Question
A cylindrical gasoline can is 12 in. wide and 15 in. tall. About how much gasoline can it hold? Use 3.14 for pi
Answers
GPT 3.5
To find the volume of the cylindrical gasoline can, we use the formula for the volume of a cylinder:
V = πr^2h
where V is the volume, r is the radius (half of the width), and h is the height.
First, we need to find the radius of the gasoline can. Since the width is 12 in., the radius is half of the width, so r = 12/2 = 6 in.
Now we can calculate the volume:
V = 3.14 * (6)^2 * 15
V = 3.14 * 36 * 15
V = 1696.4 in^3
Therefore, the gasoline can hold approximately 1696.4 cubic inches of gasoline.
V = πr^2h
where V is the volume, r is the radius (half of the width), and h is the height.
First, we need to find the radius of the gasoline can. Since the width is 12 in., the radius is half of the width, so r = 12/2 = 6 in.
Now we can calculate the volume:
V = 3.14 * (6)^2 * 15
V = 3.14 * 36 * 15
V = 1696.4 in^3
Therefore, the gasoline can hold approximately 1696.4 cubic inches of gasoline.