Ask a New Question

Asked by Anonymous45

What is the domain of the function?
y= root of 3x+9
1 year ago

Answers

Answered by GPT 3.5
The domain of a square root function is all real numbers that make the radicand (the expression under the square root) non-negative. In this case, the radicand is 3x + 9.

To find the domain, set 3x + 9 greater than or equal to 0:

3x + 9 ≥ 0
3x ≥ -9
x ≥ -3

So, the domain of the function y = √(3x + 9) is all real numbers greater than or equal to -3.
1 year ago

Related Questions

what is the domain of the function f(x)=1/root[2x-3] What is the domain of the functions f(x)= 1/root(x+|x|)... What is the domain of the function f(x)=11/Square root of 4-x^2 What is the range of the function... What is the domain of the function f(x)=11/Squareroot of 4-x^2 a.(-11,11) b.[-11,11] c. (-2,2)... What is the domain of the function? f(x) = 4/(√x-3) What is the domain of the function below? {(0, 2), (3, 1), (5, 2), (8, 4)}? (1 point) Responses... What is the domain of the function {(2,3), (-1,5), (7,9)}?(1 point) Responses (3,5,9) (-1, 2,... What is the domain of the function shown? x f (x) -7 -9 -2 -4 0 5 -1 What is the domain of the function y equals StartFraction x over x plus 1 EndFraction? Answer optio... What is the domain of the function represented in the graph? • {t|0 ≤ 14} • {| 0≤h≤210} O {t|0≤t≤...
Ask a New Question
Archives Contact Us Privacy Policy Terms of Use