Use the image to answer the question. Write an equation in slope-intercept form of the trend line. (1 point) y = Skip to navigation
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It seems that the image intended to provide a visual representation to help answer the question, but it is not included in the description. Can you please provide the image or a description of the trend line so I can help you write the equation in slope-intercept form?
its a line straight up and left starting at 20, 0 and ending at 40, 72 with the points being (20, 7) (11, 59) (15, 40) (20, 55) (25, 50) (35, 70) (39, 77) (41, 61)
To write the equation of the trend line in slope-intercept form, we first need to find the slope (m) and the y-intercept (b) using the given points.
The slope (m) can be calculated using the formula:
m = (y2 - y1) / (x2 - x1)
Taking the points (20, 7) and (40, 72) from the given data:
m = (72 - 7) / (40 - 20)
m = 65 / 20
m = 13/4
Next, we can use one of the points to find the y-intercept (b). Let's use point (20, 7):
7 = (13/4)*20 + b
7 = 65/2 + b
Solving for b gives:
b = 7 - 65/2
b = 7 - 32.5
b = -25.5
Therefore, the equation of the trend line in slope-intercept form is:
y = (13/4)x - 25.5
The slope (m) can be calculated using the formula:
m = (y2 - y1) / (x2 - x1)
Taking the points (20, 7) and (40, 72) from the given data:
m = (72 - 7) / (40 - 20)
m = 65 / 20
m = 13/4
Next, we can use one of the points to find the y-intercept (b). Let's use point (20, 7):
7 = (13/4)*20 + b
7 = 65/2 + b
Solving for b gives:
b = 7 - 65/2
b = 7 - 32.5
b = -25.5
Therefore, the equation of the trend line in slope-intercept form is:
y = (13/4)x - 25.5
Use the image to answer the question. The image is a line up and to the left with the points being (1, 30) (2, 35) (5,55) (7, 60) and (10,70). Write an equation in slope-intercept form of the trend line. (1 point) y =
To write the equation of the trend line in slope-intercept form, we first need to find the slope (m) and the y-intercept (b) using the given points.
The slope (m) can be calculated using the formula:
m = (y2 - y1) / (x2 - x1)
Taking the points (1, 30) and (10, 70) from the given data:
m = (70 - 30) / (10 - 1)
m = 40 / 9
m = 40/9
Next, we can use one of the points to find the y-intercept (b). Let's use point (1, 30):
30 = (40/9)*1 + b
30 = 40/9 + b
Solving for b gives:
b = 30 - 40/9
b = 270/9 - 40/9
b = (270 - 40) / 9
b = 230/9
Therefore, the equation of the trend line in slope-intercept form is:
y = (40/9)x + 230/9
The slope (m) can be calculated using the formula:
m = (y2 - y1) / (x2 - x1)
Taking the points (1, 30) and (10, 70) from the given data:
m = (70 - 30) / (10 - 1)
m = 40 / 9
m = 40/9
Next, we can use one of the points to find the y-intercept (b). Let's use point (1, 30):
30 = (40/9)*1 + b
30 = 40/9 + b
Solving for b gives:
b = 30 - 40/9
b = 270/9 - 40/9
b = (270 - 40) / 9
b = 230/9
Therefore, the equation of the trend line in slope-intercept form is:
y = (40/9)x + 230/9
1 answer