Asked by halp
Use the image to answer the question. Write an equation in slope-intercept form of the trend line. (1 point) y = Skip to navigation
Answers
Answered by
halp
its a line straight up and left starting at 20, 0 and ending at 40, 72 with the points being (20, 7) (11, 59) (15, 40) (20, 55) (25, 50) (35, 70) (39, 77) (41, 61)
Answered by
halp
Use the image to answer the question. The image is a line up and to the left with the points being (1, 30) (2, 35) (5,55) (7, 60) and (10,70). Write an equation in slope-intercept form of the trend line. (1 point) y =
Answered by
GPT 3.5
It seems that the image intended to provide a visual representation to help answer the question, but it is not included in the description. Can you please provide the image or a description of the trend line so I can help you write the equation in slope-intercept form?
Answered by
GPT 3.5
To write the equation of the trend line in slope-intercept form, we first need to find the slope (m) and the y-intercept (b) using the given points.
The slope (m) can be calculated using the formula:
m = (y2 - y1) / (x2 - x1)
Taking the points (20, 7) and (40, 72) from the given data:
m = (72 - 7) / (40 - 20)
m = 65 / 20
m = 13/4
Next, we can use one of the points to find the y-intercept (b). Let's use point (20, 7):
7 = (13/4)*20 + b
7 = 65/2 + b
Solving for b gives:
b = 7 - 65/2
b = 7 - 32.5
b = -25.5
Therefore, the equation of the trend line in slope-intercept form is:
y = (13/4)x - 25.5
The slope (m) can be calculated using the formula:
m = (y2 - y1) / (x2 - x1)
Taking the points (20, 7) and (40, 72) from the given data:
m = (72 - 7) / (40 - 20)
m = 65 / 20
m = 13/4
Next, we can use one of the points to find the y-intercept (b). Let's use point (20, 7):
7 = (13/4)*20 + b
7 = 65/2 + b
Solving for b gives:
b = 7 - 65/2
b = 7 - 32.5
b = -25.5
Therefore, the equation of the trend line in slope-intercept form is:
y = (13/4)x - 25.5
Answered by
GPT 3.5
To write the equation of the trend line in slope-intercept form, we first need to find the slope (m) and the y-intercept (b) using the given points.
The slope (m) can be calculated using the formula:
m = (y2 - y1) / (x2 - x1)
Taking the points (1, 30) and (10, 70) from the given data:
m = (70 - 30) / (10 - 1)
m = 40 / 9
m = 40/9
Next, we can use one of the points to find the y-intercept (b). Let's use point (1, 30):
30 = (40/9)*1 + b
30 = 40/9 + b
Solving for b gives:
b = 30 - 40/9
b = 270/9 - 40/9
b = (270 - 40) / 9
b = 230/9
Therefore, the equation of the trend line in slope-intercept form is:
y = (40/9)x + 230/9
The slope (m) can be calculated using the formula:
m = (y2 - y1) / (x2 - x1)
Taking the points (1, 30) and (10, 70) from the given data:
m = (70 - 30) / (10 - 1)
m = 40 / 9
m = 40/9
Next, we can use one of the points to find the y-intercept (b). Let's use point (1, 30):
30 = (40/9)*1 + b
30 = 40/9 + b
Solving for b gives:
b = 30 - 40/9
b = 270/9 - 40/9
b = (270 - 40) / 9
b = 230/9
Therefore, the equation of the trend line in slope-intercept form is:
y = (40/9)x + 230/9