n.

Long Description (if needed) The net appears as three horizontal rectangles joined one on top of another. The sides of the middle rectangle are drawn with dashed lines. The width of the rectangles is 100 units. The height of the middle rectangle is 24 units. The middle rectangle has a right triangle adjoining its left side. The length of the hypotenuse of the triangle is 25 units and the length of its horizontal side at the top of the triangle is 7 units. An unmarked triangle the same size and shape as the other triangle adjoins the right side of the middle rectangle. The height of the top triangle is 7 units.

The net of a triangular prism is shown. What is the surface area of the triangular prism?

(1 point)
Responses

5,684 square units
5,684 square units

5,936 square units
5,936 square units

5,668 square units
5,668 square units

5,768 square units

1 answer

To find the surface area of the triangular prism, we need to find the area of each of the five faces and then add them all together.

1. 2 triangles:
- Area of one triangle = (1/2) * base * height
- Area of one triangle = (1/2) * 7 * 24 = 84 square units
- Since there are 2 triangles, the total area for both triangles = 2 * 84 = 168 square units

2. 3 rectangles:
- Area of one rectangular face = length * width
- Area of one rectangular face = 7 * 100 = 700 square units
- Since there are 3 rectangles, the total area for all rectangles = 3 * 700 = 2100 square units

Adding all the areas together:
168 (triangles) + 2100 (rectangles) = 2268 square units

Therefore, the surface area of the triangular prism is 2268 square units.

None of the given options match this calculated surface area.