To find the surface area of the triangular prism, we need to calculate the area of all of its faces.
The triangular prism has 3 rectangular faces and 2 triangular faces.
1. The two triangular faces:
The area of one triangle is (base * height) / 2.
Each triangle has a base of 3 meters and a height of 2.6 meters.
So, the area of one triangle is (3 * 2.6) / 2 = 7.8 square meters.
Since there are two triangles, the total area of the triangular faces is 2 * 7.8 = 15.6 square meters.
2. The three rectangular faces:
Each rectangle has a length of 8 meters and a width of 3 meters.
So, the area of one rectangular face is 8 * 3 = 24 square meters.
Since there are three rectangles, the total area of the rectangular faces is 3 * 24 = 72 square meters.
Now, add the area of the triangular faces and the rectangular faces together:
15.6 + 72 = 87.6 square meters.
Therefore, the surface area of the triangular prism shown as a net is approximately 87.6 square meters.
Use the image to answer the question.
An illustration shows a two-dimensional net of a triangular prism with all of its sides open and visible. The net appears as three horizontal rectangles joined one on top of another. All 4 sides of the middle rectangle are drawn with dashed lines. The length of all the rectangles is 8 meters. The width of all the rectangles is 3 meters. Two identical triangles adjoin the middle rectangle at the left and right, with the perpendicular height of the triangles measuring 2.6 meters.
What is the surface area of the triangular prism shown as a net? Round the answer to the nearest tenth.
(1 point)
m2
1 answer