The Math club sold slices of pizza P at a profit of three dollars each in cash of soda S at two dollars each to raise money for a trip. They sold two items and made a profit of 550 right the pair of linear equations that model the solution

Answer 1

Let x be the number of slices of pizza sold and y be the number of cans of soda sold.

The profit made from selling slices of pizza is 3x and the profit made from selling cans of soda is 2y.

Given that the total profit made is $550, the equation can be written as:

3x + 2y = 550

Since they sold two items, let's assume they sold the same number of slices of pizza and cans of soda. Therefore, x = y.

Substitute x = y into the equation above:

3(x) + 2(x) = 550
5x = 550
x = 110

Now that we have the number of slices of pizza sold, we can substitute x back into the equation to find the number of soda cans sold:

3(110) + 2y = 550
330 + 2y = 550
2y = 220
y = 110

So, the pair of linear equations that model the solution are:

3x + 2y = 550
x = y
110 slices of pizza and 110 cans of soda were sold to make a profit of $550.