To find the surface area of the triangular prism, we first need to calculate the area of the three rectangles. The top and bottom rectangles both have an area of 10 ft x 24 ft = 240 ft² each. The middle rectangle, which has all sides with dashed lines in the net, has an area of 10 ft x 10 ft =100 ft².
The two right triangles each have an area of 1/2 x base x height, which is 1/2 x 10 ft x 24 ft = 120 ft² each.
Therefore, the total surface area of the triangular prism is: 2(240 ft²) + 100 ft² + 2(120 ft²) = 480 ft² + 100 ft² + 240 ft² = 820 ft².
The correct answer is 820 ft².
Use the image to answer the question.
An illustration shows a two-dimensional net of a triangular prism with all of its sides open and visible. The net appears as three vertical rectangles placed vertically one on top of the other. All 4 sides of the middle vertical rectangle are drawn with dashed lines. The width of the rectangles is 10 feet. The length of the middle rectangle is 24 feet. Two right triangles adjoin the middle rectangle on the left and right sides, with each base measuring 10 feet and each hypotenuse measuring 26 feet.
Using the net of the triangular prism, what is its surface area?
(1 point)
Responses
720 ft.2
720 ft. squared
240 ft.2
240 ft. squared
1,200 ft.2
1,200 mi. squared
840 ft.2
840 ft. squared
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