Asked by mike

What am I doing wrong I am using the Gauss Jordan method to calculate this answer and some other students are coming up with differant answers.
Problem is
3x+y+z=5,
x+5y-z=-8,
10x+7y+z=2

My answer is (-6z+3,7z-4
_________, z
( 11 11)
Where I have +3 they have +33 and where I have -4 they have -44 Can you let me know how they came up with the larger numbers
Answered by bobpursley
This does not make sense to me. You have three equations, three unknowns. YOu can solve for x,y,z. Whatever you are doing, I don't understand.
Answered by mike
What am I doing wrong I am using the Gauss Jordan method to calculate this answer and some other students are coming up with differant answers.
Problem is
3x+y+z=5,
x+5y-z=-8,
10x+7y+z=2

Answers are
1-(-6z+3/11, 7z-4/11,z)

2-(-6z+33/11,7z-44/11)

I got #1 for my answer and some got #2 which one is right. Some got all kinds of numbers.

Answered by bobpursley
well, I didn't get anything like that, I got a specific number solution for x, y, and z.
When you say "calculate" and answer, that to me implies looking for a specific solution.

Here is a Gauss Jordan applet, check your work
http://www.gregthatcher.com/Mathematics/GaussJordan.aspx
Answered by mike
My mistake New at this Question should be Use the Gauss-Jordn method to solve the system of equations.
Answered by bobpursley
well, both your 1) and 2) are NOT solutions. Solutions have specific values for x,y, and z.

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