The vertex form of a quadratic equation is y = a(x-h)^2 + k, where (h, k) is the vertex of the parabola.
In this case, the equation is y = -6(x-7)^2 + 3, which means a = -6, h = 7, and k = 3.
Therefore, the vertex of the parabola is (7, 3).
The axis of symmetry of the parabola is the vertical line that passes through the vertex. In this case, the axis of symmetry is x = 7.
What is the vertex and axis of symmetry of the equation? y = -6 ( x - 7) ^2 + 3
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