The sides of a triangular path measure 7, 9, and 11. Find the perimeter of a similar triangle in which the shortest side has a length of 21 meters.

1 answer

To find the perimeter of the similar triangle, we need to determine the scale factor relating the sides of the two triangles.

Let the scale factor be k. We can set up a proportion based on the corresponding sides of the two triangles:

\( \frac{7}{21} = \frac{9k}{9} = \frac{11k}{11} \)

Solving this proportion, we find that \( k = \frac{21}{7} = 3 \).

Therefore, the sides of the similar triangle are 21, 27, and 33 meters.

The perimeter of the similar triangle is \( 21 + 27 + 33 = 81 \) meters.