nP³ = n(n-1)(n-2)
nP⁰ = n
nP³\nC² + nP⁰ = n(n-1)(n-2)\2 + n
Simplify the above equation by expanding n(n-1)(n-2)/2:
n(n-1)(n-2)/2 = (n³ - 3n² + 2n)/2
Therefore, n(n-1)(n-2)/2 + n = (n³ - 3n² + 2n)/2 + n
Simplify the above expression further by combining like terms:
(n³ - 3n² + 2n)/2 + n = n³/2 - 3n²/2 + 2n/2 + n
= n³/2 - 3n²/2 + n/2 + n
Hence, the simplified expression is n³/2 - 3n²/2 + n/2 + n
Simplify nP³\nC²+nP⁰
1 answer