Question

A football is kicked with a speed of 18 m/s at an angle of 65° to the horizontal. What are the respective horizontal and vertical components of the initial velocity of the football?
7.6 m/s, 16 m/s
9 m/s, 9 m/s
13 m/s, 8.4 m/s
• 16 m/s, 7.6 m/s
8 m/s, 17 m/s

Answer 1

To find the horizontal and vertical components of the initial velocity of the football, we can use trigonometry.

The horizontal component of the initial velocity can be found using the formula: Vx = V * cos(theta), where V is the initial velocity and theta is the angle of the velocity.

Vx = 18 m/s * cos(65°)
Vx = 18 m/s * 0.42262
Vx = 7.6 m/s

The vertical component of the initial velocity can be found using the formula: Vy = V * sin(theta), where V is the initial velocity and theta is the angle of the velocity.

Vy = 18 m/s * sin(65°)
Vy = 18 m/s * 0.90631
Vy = 16 m/s

Therefore, the respective horizontal and vertical components of the initial velocity of the football are 7.6 m/s and 16 m/s. The correct answer is 7.6 m/s, 16 m/s.