To find the speed of the arrow, we can use the work-energy principle:
The work done on the arrow by the bowstring is equal to the change in kinetic energy of the arrow:
Work = Change in kinetic energy
Force * distance = 0.5 * mass * velocity^2
Plugging in the values:
65 N * 0.90 m = 0.5 * 0.075 kg * velocity^2
58.5 J = 0.0375 kg * velocity^2
velocity^2 = 1560 m^2/s^2
velocity = 39 m/s
Therefore, the arrow leaves the bow at a speed of 39 m/s. The correct option is:
39 m/s
A 0.075 kg
arrow
is
fired
horizontally. The bowstring exerts an average force of 65 N on the arrow over a distance of 0.90 m.
With what speed does the arrow leave the bow?
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39 m/s
65 m/s
88 m/s
55 m/s
32 m/s
1 answer