Question
A shot-putter puts a shot (weight =
71.1 N) that leaves his hand at a distance of 1.52 m above the ground. Find the work done by the gravitational force when the shot has risen to a height of 2.13 m above the ground and determine the change in the gravitational potential energy of the shot.
71.1 N) that leaves his hand at a distance of 1.52 m above the ground. Find the work done by the gravitational force when the shot has risen to a height of 2.13 m above the ground and determine the change in the gravitational potential energy of the shot.
Answers
GPT 3.5
To find the work done by the gravitational force, we can use the formula:
Work = change in gravitational potential energy
The work done by gravity can be calculated by the formula:
W = -mgh
where:
W = work done by gravity
m = mass of the shot (m = 71.1 N / 9.81 m/s^2 ≈ 7.25 kg)
g = acceleration due to gravity (g = 9.81 m/s^2)
h = change in height (2.13 m - 1.52 m = 0.61 m)
Plugging in the values, we get:
W = -7.25 kg * 9.81 m/s^2 * 0.61 m
W = -43.03 Joules
Therefore, the work done by the gravitational force when the shot has risen to a height of 2.13 m above the ground is -43.03 Joules.
To determine the change in gravitational potential energy of the shot, we use the formula:
Change in potential energy = mgh
The change in potential energy can be calculated by:
ΔPE = 7.25 kg * 9.81 m/s^2 * (2.13 m - 1.52 m)
ΔPE = 7.25 kg * 9.81 m/s^2 * 0.61 m
ΔPE = 43.03 Joules
Therefore, the change in gravitational potential energy of the shot is 43.03 Joules.
Work = change in gravitational potential energy
The work done by gravity can be calculated by the formula:
W = -mgh
where:
W = work done by gravity
m = mass of the shot (m = 71.1 N / 9.81 m/s^2 ≈ 7.25 kg)
g = acceleration due to gravity (g = 9.81 m/s^2)
h = change in height (2.13 m - 1.52 m = 0.61 m)
Plugging in the values, we get:
W = -7.25 kg * 9.81 m/s^2 * 0.61 m
W = -43.03 Joules
Therefore, the work done by the gravitational force when the shot has risen to a height of 2.13 m above the ground is -43.03 Joules.
To determine the change in gravitational potential energy of the shot, we use the formula:
Change in potential energy = mgh
The change in potential energy can be calculated by:
ΔPE = 7.25 kg * 9.81 m/s^2 * (2.13 m - 1.52 m)
ΔPE = 7.25 kg * 9.81 m/s^2 * 0.61 m
ΔPE = 43.03 Joules
Therefore, the change in gravitational potential energy of the shot is 43.03 Joules.