Write the miller indices for the plane below. Intercepts A (2/3, recurring 1,1/2) B (1/2,1/2,1)

Answer 1

To find the miller indices, we need to take the reciprocals of the intercepts and then multiply by a common factor to get integers.

Given intercepts A: (2/3, recurring 1, 1/2) and B: (1/2, 1/2, 1), we take the reciprocal of each intercept to get:

A: (3/2, 1, 2)
B: (2, 2, 1)

Next, we multiply by a common factor to get integers. Let's multiply by 2:

A: (3, 2, 4)
B: (4, 4, 2)

Therefore, the miller indices for the plane with intercepts A and B are (3, 2, 4).