First, identify the coefficients in the equation:
a = 4
b = 3
c = -10
Now, plug the coefficients into the quadratic formula:
x = (-b ± √(b² - 4ac)) / 2a
x = (-3 ± √(3² - 4*4*(-10))) / (2*4)
x = (-3 ± √(9 + 160)) / 8
x = (-3 ± √169) / 8
x = (-3 ± 13) / 8
Now we have two possible solutions:
x1 = (-3 + 13) / 8
x1 = 10 / 8
x1 = 1.25
x2 = (-3 - 13) / 8
x2 = -16 / 8
x2 = -2
Therefore, the solutions to the equation 4x^2 + 3x - 10 = 0 are x = 1.25 and x = -2.
Solve the equation using the quadratic formula.
4 x squared plus 3 x minus 10 equals 0
1 answer