1. To determine the amplitude of y = -16 cos(x), we need to look at the coefficient in front of the cosine function. In this case, the coefficient is -16, which represents the amplitude. Therefore, the amplitude is 16.
2. To determine the amplitude of y = -sin(x), we need to look at the coefficient in front of the sine function. In this case, there is no coefficient, so we assume it to be 1. Therefore, the amplitude is 1.
3. To determine the domain of y = -5 cos(x), we need to consider the possible values of x. Since the cosine function is defined for all real numbers, there are no restrictions on the domain. Therefore, the domain is (-∞, ∞).
4. To determine the range of y = -10 sin(x), we need to consider the possible values of y. The sine function has a range between -1 and 1, inclusive. So, when we multiply by -10 in front of the sine function, we get the range of y to be between -10 and 10, inclusive. Therefore, the range is [-10, 10].
5. To determine the period of y = -5 cos(2πx), we need to look at the coefficient in front of x, which is 2π. The period of the cosine function is given by 2π divided by the coefficient. Therefore, the period is 2π / (2π) = 1.
6. To determine the phase shift of y = -5 cos(3x - 2), we need to compare the input to the cosine function (3x - 2) to the standard expression of the cosine function, which is just x. In this case, the phase shift is given by setting 3x - 2 equal to 0 and solving for x. Therefore, the phase shift is x = 2/3.
7. To solve y = -sin(x) for x = π, we substitute π into the equation. Therefore, y = -sin(π) = 0.
8. To solve y = -sin(x) for x = -6π, we substitute -6π into the equation. Therefore, y = -sin(-6π) = 0.
9. The equation of the graph in the handout is not provided in the question.
10. The equation of the graph in the handout is not provided in the question.