The equation for the dissociation of HI is:
HI → H+ + I-
Since 1 molecule of HI dissociates into 1 H+ ion and 1 I- ion, the concentration of H+ ions is equal to the concentration of HI, which is 1.0 × 10^-6 M.
Therefore, pH = -log[H+]
pH = -log(1.0 × 10^-6)
pH = -(-6)
pH = 6.00
So, the pH of a 1.0 × 10^-6 M solution of HI is 6.00.
Calculate the pH of a 1.0 × 10^-6 M solution of HI. Round your answer to 2 decimal places.
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