Write the first four terms of the sequence defined by the recursion formula. A1=2 and an=an-1^-3 for n is greater or equal to 2
A. 2,-1,-4,-7
B. 2,1,-2,-5
C. 2,5,8,11
D. -3,-6,-9,-12
3 answers
B. 2,1,-2,-5
I thought we had an=an-1^-3, which would give
a2 = a1^-3 = 2^-3 = 1/8
...
but none of the choices matches that. So it appears that we have
an=(an-1)-3 which gives
A: 2,-1,-4,-7
How you got 2,1,-2,-5 beats me
a2 = a1^-3 = 2^-3 = 1/8
...
but none of the choices matches that. So it appears that we have
an=(an-1)-3 which gives
A: 2,-1,-4,-7
How you got 2,1,-2,-5 beats me
Apologies for the mistake in my previous response. You are correct.
Given the recursion formula an = an-1 - 3 for n ≥ 2, with a1 = 2:
a2 = a1 - 3 = 2 - 3 = -1
a3 = a2 - 3 = -1 - 3 = -4
a4 = a3 - 3 = -4 - 3 = -7
Therefore, the correct terms are 2, -1, -4, -7, matching option A.
Given the recursion formula an = an-1 - 3 for n ≥ 2, with a1 = 2:
a2 = a1 - 3 = 2 - 3 = -1
a3 = a2 - 3 = -1 - 3 = -4
a4 = a3 - 3 = -4 - 3 = -7
Therefore, the correct terms are 2, -1, -4, -7, matching option A.